288=2x^2+36x

Solution for 288=2x^2+36x equation:

288=2x^2+36x

We move all terms to the left:

288-(2x^2+36x)=0

We get rid of parentheses

-2x^2-36x+288=0

a = -2; b = -36; c = +288;
Δ = b2-4ac
Δ = -362-4·(-2)·288
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-60}{2*-2}=\frac{-24}{-4}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+60}{2*-2}=\frac{96}{-4}
=-24
$